(-3a+2b-c)+(4b+3a-2c)=6b-3c

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Solution for (-3a+2b-c)+(4b+3a-2c)=6b-3c equation:


Simplifying
(-3a + 2b + -1c) + (4b + 3a + -2c) = 6b + -3c

Remove parenthesis around (-3a + 2b + -1c)
-3a + 2b + -1c + (4b + 3a + -2c) = 6b + -3c

Reorder the terms:
-3a + 2b + -1c + (3a + 4b + -2c) = 6b + -3c

Remove parenthesis around (3a + 4b + -2c)
-3a + 2b + -1c + 3a + 4b + -2c = 6b + -3c

Reorder the terms:
-3a + 3a + 2b + 4b + -1c + -2c = 6b + -3c

Combine like terms: -3a + 3a = 0
0 + 2b + 4b + -1c + -2c = 6b + -3c
2b + 4b + -1c + -2c = 6b + -3c

Combine like terms: 2b + 4b = 6b
6b + -1c + -2c = 6b + -3c

Combine like terms: -1c + -2c = -3c
6b + -3c = 6b + -3c

Add '-6b' to each side of the equation.
6b + -6b + -3c = 6b + -6b + -3c

Combine like terms: 6b + -6b = 0
0 + -3c = 6b + -6b + -3c
-3c = 6b + -6b + -3c

Combine like terms: 6b + -6b = 0
-3c = 0 + -3c
-3c = -3c

Add '3c' to each side of the equation.
-3c + 3c = -3c + 3c

Combine like terms: -3c + 3c = 0
0 = -3c + 3c

Combine like terms: -3c + 3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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