(-3/8x+5)+(1/8x-3)=0

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Solution for (-3/8x+5)+(1/8x-3)=0 equation: 



(-3/8x+5)+(1/8x-3)=0



Domain of the equation: 8x+5)!=0

x∈R





Domain of the equation: 8x-3)!=0

x∈R



We get rid of parentheses

-3/8x+1/8x+5-3=0

We multiply all the terms by the denominator


5*8x-3*8x-3+1=0

We add all the numbers together, and all the variables

5*8x-3*8x-2=0

Wy multiply elements

40x-24x-2=0

We add all the numbers together, and all the variables

16x-2=0

We move all terms containing x to the left, all other terms to the right

16x=2

x=2/16

x=1/8

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