(-3/8)r+41=-22

Solution for (-3/8)r+41=-22 equation:

(-3/8)r+41=-22

We move all terms to the left:

(-3/8)r+41-(-22)=0


Domain of the equation: 8)r!=0

r!=0/1

r!=0

r∈R


We add all the numbers together, and all the variables

(-3/8)r+63=0

We multiply parentheses

-3r^2+63=0

a = -3; b = 0; c = +63;
Δ = b2-4ac
Δ = 02-4·(-3)·63
Δ = 756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{756}=\sqrt{36*21}=\sqrt{36}*\sqrt{21}=6\sqrt{21}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{21}}{2*-3}=\frac{0-6\sqrt{21}}{-6}
=-\frac{6\sqrt{21}}{-6}
=-\frac{\sqrt{21}}{-1}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{21}}{2*-3}=\frac{0+6\sqrt{21}}{-6}
=\frac{6\sqrt{21}}{-6}
=\frac{\sqrt{21}}{-1}
$