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(-3-x)x=-400
We move all terms to the left:
(-3-x)x-(-400)=0
We add all the numbers together, and all the variables
(-1x-3)x-(-400)=0
We add all the numbers together, and all the variables
(-1x-3)x+400=0
We multiply parentheses
-1x^2-3x+400=0
a = -1; b = -3; c = +400;
Δ = b2-4ac
Δ = -32-4·(-1)·400
Δ = 1609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{1609}}{2*-1}=\frac{3-\sqrt{1609}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{1609}}{2*-1}=\frac{3+\sqrt{1609}}{-2} $
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