(-3+i)(-3-i)=

Solution for (-3+i)(-3-i)= equation:

Simplifying
(-3 + i)(-3 + -1i) = 0

Multiply (-3 + i) * (-3 + -1i)
(-3(-3 + -1i) + i(-3 + -1i)) = 0
((-3 * -3 + -1i * -3) + i(-3 + -1i)) = 0
((9 + 3i) + i(-3 + -1i)) = 0
(9 + 3i + (-3 * i + -1i * i)) = 0
(9 + 3i + (-3i + -1i2)) = 0

Combine like terms: 3i + -3i = 0
(9 + 0 + -1i2) = 0
(9 + -1i2) = 0

Solving
9 + -1i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -1i2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -1i2 = 0 + -9
-1i2 = 0 + -9

Combine like terms: 0 + -9 = -9
-1i2 = -9

Divide each side by '-1'.
i2 = 9

Simplifying
i2 = 9

Take the square root of each side:
i = {-3, 3}