(-3+(2/3)(6x-42))=-51

Solution for (-3+(2/3)(6x-42))=-51 equation:

(-3+(2/3)(6x-42))=-51

We move all terms to the left:

(-3+(2/3)(6x-42))-(-51)=0


Domain of the equation: 3)(6x-42))!=0

x∈R


We add all the numbers together, and all the variables

(-3+(+2/3)(6x-42))-(-51)=0

We add all the numbers together, and all the variables

(-3+(+2/3)(6x-42))+51=0

We multiply parentheses ..

(-3+(+12x^2+2/3*-42))+51=0

We multiply all the terms by the denominator


(-3+(+12x^2+2+51*3*-42))=0


We calculate terms in parentheses: +(-3+(+12x^2+2+51*3*-42)), so:

-3+(+12x^2+2+51*3*-42)

determiningTheFunctionDomain
(+12x^2+2+51*3*-42)-3

We get rid of parentheses

12x^2+2-42-3+51*3*

We add all the numbers together, and all the variables

12x^2

Back to the equation:

+(12x^2)


a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$