(-2x-1)/6=(1-3x)/9

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Solution for (-2x-1)/6=(1-3x)/9 equation: 


x in (-oo:+oo)

(-2*x-1)/6 = (1-(3*x))/9 // - (1-(3*x))/9

(-2*x-1)/6-((1-(3*x))/9) = 0

(-2*x-1)/6-((1-3*x)/9) = 0

(-2*x-1)/6+(-1*(1-3*x))/9 = 0

(9*(-2*x-1))/(6*9)+(-1*6*(1-3*x))/(6*9) = 0

9*(-2*x-1)-1*6*(1-3*x) = 0

-15 = 0

-15/(6*9) = 0

-15/(6*9) = 0 // * 6*9

-15 = 0

-15 = 0

x belongs to the empty set

x belongs to the empty set

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