(-2x+3)(-2x-3)=4x(x+1)

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Solution for (-2x+3)(-2x-3)=4x(x+1) equation: 



(-2x+3)(-2x-3)=4x(x+1)

We move all terms to the left:

(-2x+3)(-2x-3)-(4x(x+1))=0

We multiply parentheses ..

(+4x^2+6x-6x-9)-(4x(x+1))=0



We calculate terms in parentheses: -(4x(x+1)), so:

4x(x+1)

We multiply parentheses

4x^2+4x

Back to the equation:

-(4x^2+4x)



We get rid of parentheses

4x^2-4x^2+6x-6x-4x-9=0

We add all the numbers together, and all the variables

-4x-9=0

We move all terms containing x to the left, all other terms to the right

-4x=9

x=9/-4

x=-2+1/4

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