(-2/3)d+3=19

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Solution for (-2/3)d+3=19 equation: 



(-2/3)d+3=19

We move all terms to the left:

(-2/3)d+3-(19)=0



Domain of the equation: 3)d!=0

d!=0/1

d!=0

d∈R



We add all the numbers together, and all the variables

(-2/3)d-16=0

We multiply parentheses

-2d^2-16=0

a = -2; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-2)·(-16)
Δ = -128
Delta is less than zero, so there is no solution for the equation

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