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(-12+2x)+6=2(x+-3)
We move all terms to the left:
(-12+2x)+6-(2(x+-3))=0
We add all the numbers together, and all the variables
(2x-12)-(2(x-3))+6=0
We get rid of parentheses
2x-(2(x-3))-12+6=0
We calculate terms in parentheses: -(2(x-3)), so:We add all the numbers together, and all the variables
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
2x-(2x-6)-6=0
We get rid of parentheses
2x-2x+6-6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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