(-12)=3(k-2)

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Solution for (-12)=3(k-2) equation: 



(-12)=3(k-2)

We move all terms to the left:

(-12)-(3(k-2))=0

We add all the numbers together, and all the variables

-(3(k-2))-12=0



We calculate terms in parentheses: -(3(k-2)), so:

3(k-2)

We multiply parentheses

3k-6

Back to the equation:

-(3k-6)



We get rid of parentheses

-3k+6-12=0

We add all the numbers together, and all the variables

-3k-6=0

We move all terms containing k to the left, all other terms to the right

-3k=6

k=6/-3

k=-2

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