(-10x+58)+(6x-41)=11

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Solution for (-10x+58)+(6x-41)=11 equation: 



(-10x+58)+(6x-41)=11

We move all terms to the left:

(-10x+58)+(6x-41)-(11)=0

We get rid of parentheses

-10x+6x+58-41-11=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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