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(-10+2x)(6+x)=0
We add all the numbers together, and all the variables
(2x-10)(x+6)=0
We multiply parentheses ..
(+2x^2+12x-10x-60)=0
We get rid of parentheses
2x^2+12x-10x-60=0
We add all the numbers together, and all the variables
2x^2+2x-60=0
a = 2; b = 2; c = -60;
Δ = b2-4ac
Δ = 22-4·2·(-60)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-22}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+22}{2*2}=\frac{20}{4} =5 $
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