(-10)=(2x+3)(-1-x)

Solution for (-10)=(2x+3)(-1-x) equation:

(-10)=(2x+3)(-1-x)

We move all terms to the left:

(-10)-((2x+3)(-1-x))=0

We add all the numbers together, and all the variables

-((2x+3)(-1x-1))+(-10)=0

We add all the numbers together, and all the variables

-((2x+3)(-1x-1))-10=0

We multiply parentheses ..

-((-2x^2-2x-3x-3))-10=0


We calculate terms in parentheses: -((-2x^2-2x-3x-3)), so:

(-2x^2-2x-3x-3)

We get rid of parentheses

-2x^2-2x-3x-3

We add all the numbers together, and all the variables

-2x^2-5x-3

Back to the equation:

-(-2x^2-5x-3)


We get rid of parentheses

2x^2+5x+3-10=0

We add all the numbers together, and all the variables

2x^2+5x-7=0

a = 2; b = 5; c = -7;
Δ = b2-4ac
Δ = 52-4·2·(-7)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-9}{2*2}=\frac{-14}{4}
=-3+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+9}{2*2}=\frac{4}{4}
=1
$