(-1/6)9x-12)+(1/2)(x+2)=x+3

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Solution for (-1/6)9x-12)+(1/2)(x+2)=x+3 equation: 



(-1/6)9x-12)+(1/2)(x+2)=x+3

We move all terms to the left:

(-1/6)9x-12)+(1/2)(x+2)-(x+3)=0



Domain of the equation: 6)9x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)(x!=0

x∈R



We add all the numbers together, and all the variables

(-1/6)9x+1/2)(x+2)-(x-12)+(+3)=0

We add all the numbers together, and all the variables

(-1/6)9x+1/2)(x+2)-(x=0

We multiply parentheses

-9x^2+1/2)(x+2)-(x=0

We multiply all the terms by the denominator


-9x^2*2)(x-x*2)(x+1+2=0

We add all the numbers together, and all the variables

-9x^2*2)(+x-x*2)(x+1+2=0

We add all the numbers together, and all the variables

-9x^2*2)(+x-x*2)(x+3=0

Wy multiply elements

-18x^3-2x^2+x+3=0

We do not support expression: x^3

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