(-1/3)x-4=1/3+16

Solution for (-1/3)x-4=1/3+16 equation:

(-1/3)x-4=1/3+16

We move all terms to the left:

(-1/3)x-4-(1/3+16)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We multiply parentheses

-1x^2-4-(1/3+16)=0

We get rid of parentheses

-1x^2-4-16-1/3=0

We multiply all the terms by the denominator


-1x^2*3-1-4*3-16*3=0

We add all the numbers together, and all the variables

-1x^2*3-61=0

Wy multiply elements

-3x^2-61=0

a = -3; b = 0; c = -61;
Δ = b2-4ac
Δ = 02-4·(-3)·(-61)
Δ = -732
Delta is less than zero, so there is no solution for the equation