(-1/3)(2x+5)=7

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Solution for (-1/3)(2x+5)=7 equation: 



(-1/3)(2x+5)=7

We move all terms to the left:

(-1/3)(2x+5)-(7)=0



Domain of the equation: 3)(2x+5)!=0

x∈R



We multiply parentheses ..

(-2x^2-1/3*5)-7=0

We multiply all the terms by the denominator


(-2x^2-1-7*3*5)=0

We get rid of parentheses

-2x^2-1-7*3*5=0

We add all the numbers together, and all the variables

-2x^2-106=0

a = -2; b = 0; c = -106;
Δ = b2-4ac
Δ = 02-4·(-2)·(-106)
Δ = -848
Delta is less than zero, so there is no solution for the equation

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