(-1/(4x))+(1/(4x+16))=(1/4)

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Solution for (-1/(4x))+(1/(4x+16))=(1/4) equation:


D( x )

4*x+16 = 0

4*x = 0

4*x+16 = 0

4*x+16 = 0

4*x+16 = 0 // - 16

4*x = -16 // : 4

x = -16/4

x = -4

4*x = 0

4*x = 0

4*x = 0 // : 4

x = 0

x in (-oo:-4) U (-4:0) U (0:+oo)

1/(4*x+16)-1/(4*x) = 1/4 // - 1/4

1/(4*x+16)-1/(4*x)-(1/4) = 0

1/(4*x+16)-1/(4*x)-1/4 = 0

(1*4*4*x)/(4*4*x*(4*x+16))+(-1*4*(4*x+16))/(4*4*x*(4*x+16))+(-1*4*x*(4*x+16))/(4*4*x*(4*x+16)) = 0

1*4*4*x-1*4*(4*x+16)-1*4*x*(4*x+16) = 0

-16*x^2-64*x-64 = 0

-16*x^2-64*x-64 = 0

-16*(x^2+4*x+4) = 0

x^2+4*x+4 = 0

DELTA = 4^2-(1*4*4)

DELTA = 0

x = -4/(1*2)

x = -2 or x = -2

-16*(x+2)^2 = 0

(-16*(x+2)^2)/(4*4*x*(4*x+16)) = 0

(-16*(x+2)^2)/(4*4*x*(4*x+16)) = 0 // * 4*4*x*(4*x+16)

-16*(x+2)^2 = 0

x+2 = 0 // - 2

x = -2

x in { -2, -2 }

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