(-1+2i)(2+5i)=

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Solution for (-1+2i)(2+5i)= equation:


Simplifying
(-1 + 2i)(2 + 5i) = 0

Multiply (-1 + 2i) * (2 + 5i)
(-1(2 + 5i) + 2i * (2 + 5i)) = 0
((2 * -1 + 5i * -1) + 2i * (2 + 5i)) = 0
((-2 + -5i) + 2i * (2 + 5i)) = 0
(-2 + -5i + (2 * 2i + 5i * 2i)) = 0
(-2 + -5i + (4i + 10i2)) = 0

Combine like terms: -5i + 4i = -1i
(-2 + -1i + 10i2) = 0

Solving
-2 + -1i + 10i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(-2 + -5i)(1 + -2i) = 0

Subproblem 1

Set the factor '(-2 + -5i)' equal to zero and attempt to solve: Simplifying -2 + -5i = 0 Solving -2 + -5i = 0 Move all terms containing i to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -5i = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -5i = 0 + 2 -5i = 0 + 2 Combine like terms: 0 + 2 = 2 -5i = 2 Divide each side by '-5'. i = -0.4 Simplifying i = -0.4

Subproblem 2

Set the factor '(1 + -2i)' equal to zero and attempt to solve: Simplifying 1 + -2i = 0 Solving 1 + -2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2i = 0 + -1 -2i = 0 + -1 Combine like terms: 0 + -1 = -1 -2i = -1 Divide each side by '-2'. i = 0.5 Simplifying i = 0.5

Solution

i = {-0.4, 0.5}

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