((y-4)/3)+2=(y-5)/6

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Solution for ((y-4)/3)+2=(y-5)/6 equation: 


y in (-oo:+oo)

(y-4)/3+2 = (y-5)/6 // - (y-5)/6

(y-4)/3-((y-5)/6)+2 = 0

(y-4)/3+(-1*(y-5))/6+2 = 0

(6*(y-4))/(3*6)+(-1*3*(y-5))/(3*6)+(2*3*6)/(3*6) = 0

6*(y-4)-1*3*(y-5)+2*3*6 = 0

3*y-9+36 = 0

3*y+27 = 0

(3*y+27)/(3*6) = 0

(3*y+27)/(3*6) = 0 // * 3*6

3*y+27 = 0

3*y+27 = 0 // - 27

3*y = -27 // : 3

y = -27/3

y = -9

y = -9

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