((x/3)-2)+6=7x-3

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Solution for ((x/3)-2)+6=7x-3 equation: 



((x/3)-2)+6=7x-3

We move all terms to the left:

((x/3)-2)+6-(7x-3)=0

We add all the numbers together, and all the variables

((+x/3)-2)-(7x-3)+6=0

We get rid of parentheses

((+x/3)-2)-7x+3+6=0

We multiply all the terms by the denominator


((+x-7x*3)-2)+3*3)-2)+6*3)-2)=0



We calculate terms in parentheses: +((+x-7x*3)-2), so:

(+x-7x*3)-2

We get rid of parentheses

x-7x*3-2

Wy multiply elements

x-21x-2

We add all the numbers together, and all the variables

-20x-2

Back to the equation:

+(-20x-2)



We add all the numbers together, and all the variables

(-20x-2)=0

We get rid of parentheses

-20x-2=0

We move all terms containing x to the left, all other terms to the right

-20x=2

x=2/-20

x=-1/10

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