((x/3)+5)=27x+15

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Solution for ((x/3)+5)=27x+15 equation:



((x/3)+5)=27x+15
We move all terms to the left:
((x/3)+5)-(27x+15)=0
We add all the numbers together, and all the variables
((+x/3)+5)-(27x+15)=0
We get rid of parentheses
((+x/3)+5)-27x-15=0
We multiply all the terms by the denominator
((+x-27x*3)+5)-15*3)+5)=0
We calculate terms in parentheses: +((+x-27x*3)+5), so:
(+x-27x*3)+5
We get rid of parentheses
x-27x*3+5
Wy multiply elements
x-81x+5
We add all the numbers together, and all the variables
-80x+5
Back to the equation:
+(-80x+5)
We add all the numbers together, and all the variables
(-80x+5)=0
We get rid of parentheses
-80x+5=0
We move all terms containing x to the left, all other terms to the right
-80x=-5
x=-5/-80
x=1/16

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