((x-5)/6)+((3x+7)/12)=2x-5

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Solution for ((x-5)/6)+((3x+7)/12)=2x-5 equation: 



((x-5)/6)+((3x+7)/12)=2x-5

We move all terms to the left:

((x-5)/6)+((3x+7)/12)-(2x-5)=0

We get rid of parentheses

((x-5)/6)+((3x+7)/12)-2x+5=0

We calculate fractions


-2x+(12x-60)/()+(18x+42)/()+5=0

We multiply all the terms by the denominator


-2x*()+(12x-60)+(18x+42)+5*()=0

We add all the numbers together, and all the variables

-2x*()+(12x-60)+(18x+42)=0

We get rid of parentheses

-2x*()+12x+18x-60+42=0

We add all the numbers together, and all the variables

30x-2x*()-18=0

We move all terms containing x to the left, all other terms to the right

30x-2x*()=18

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