((x+2)/5)+((x+4)/4)=2

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Solution for ((x+2)/5)+((x+4)/4)=2 equation: 



((x+2)/5)+((x+4)/4)=2

We move all terms to the left:

((x+2)/5)+((x+4)/4)-(2)=0

We calculate fractions


(4x+8)/()+(5x+20)/()-2=0

We multiply all the terms by the denominator


(4x+8)+(5x+20)-2*()=0

We add all the numbers together, and all the variables

(4x+8)+(5x+20)=0

We get rid of parentheses

4x+5x+8+20=0

We add all the numbers together, and all the variables

9x+28=0

We move all terms containing x to the left, all other terms to the right

9x=-28

x=-28/9

x=-3+1/9

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