((x+2)/3)-1=(2x-1)/4

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Solution for ((x+2)/3)-1=(2x-1)/4 equation: 



((x+2)/3)-1=(2x-1)/4

We move all terms to the left:

((x+2)/3)-1-((2x-1)/4)=0

We calculate fractions


(4x+8)/()+(-6x+3)/()-1=0

We multiply all the terms by the denominator


(4x+8)+(-6x+3)-1*()=0

We add all the numbers together, and all the variables

(4x+8)+(-6x+3)=0

We get rid of parentheses

4x-6x+8+3=0

We add all the numbers together, and all the variables

-2x+11=0

We move all terms containing x to the left, all other terms to the right

-2x=-11

x=-11/-2

x=5+1/2

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