((x+2)/3)+4x=4

Solution for ((x+2)/3)+4x=4 equation:

((x+2)/3)+4x=4

We move all terms to the left:

((x+2)/3)+4x-(4)=0

We add all the numbers together, and all the variables

4x+((x+2)/3)-4=0

We multiply all the terms by the denominator


4x*3)+((x+2)-4*3)=0

We add all the numbers together, and all the variables

4x*3)+((x+2)=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$