((x+12)+(3x-4))/2=4x-18

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Solution for ((x+12)+(3x-4))/2=4x-18 equation: 



((x+12)+(3x-4))/2=4x-18

We move all terms to the left:

((x+12)+(3x-4))/2-(4x-18)=0

We get rid of parentheses

((x+12)+(3x-4))/2-4x+18=0

We multiply all the terms by the denominator


((x+12)+(3x-4))-4x*2+18*2=0



We calculate terms in parentheses: +((x+12)+(3x-4)), so:

(x+12)+(3x-4)

We get rid of parentheses

x+3x+12-4

We add all the numbers together, and all the variables

4x+8

Back to the equation:

+(4x+8)



We add all the numbers together, and all the variables

(4x+8)-4x*2+36=0

Wy multiply elements

(4x+8)-8x+36=0

We get rid of parentheses

4x-8x+8+36=0

We add all the numbers together, and all the variables

-4x+44=0

We move all terms containing x to the left, all other terms to the right

-4x=-44

x=-44/-4

x=+11

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