((x+1)/5)-((3x+1)/2)=3

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Solution for ((x+1)/5)-((3x+1)/2)=3 equation: 



((x+1)/5)-((3x+1)/2)=3

We move all terms to the left:

((x+1)/5)-((3x+1)/2)-(3)=0

We calculate fractions


(2x+2)/()+(-15x-5)/()-3=0

We multiply all the terms by the denominator


(2x+2)+(-15x-5)-3*()=0

We add all the numbers together, and all the variables

(2x+2)+(-15x-5)=0

We get rid of parentheses

2x-15x+2-5=0

We add all the numbers together, and all the variables

-13x-3=0

We move all terms containing x to the left, all other terms to the right

-13x=3

x=3/-13

x=-3/13

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