((x+1)/3)+((x+2)/7)=2

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Solution for ((x+1)/3)+((x+2)/7)=2 equation: 


x in (-oo:+oo)

(x+1)/3+(x+2)/7 = 2 // - 2

(x+1)/3+(x+2)/7-2 = 0

(7*(x+1))/(3*7)+(3*(x+2))/(3*7)+(-2*3*7)/(3*7) = 0

7*(x+1)+3*(x+2)-2*3*7 = 0

10*x-42+13 = 0

10*x-29 = 0

(10*x-29)/(3*7) = 0

(10*x-29)/(3*7) = 0 // * 3*7

10*x-29 = 0

10*x-29 = 0 // + 29

10*x = 29 // : 10

x = 29/10

x = 29/10

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