((n-1)(4(n-1))(2(4(n-1))))/3=26

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Solution for ((n-1)(4(n-1))(2(4(n-1))))/3=26 equation: 



((n-1)(4(n-1))(2(4(n-1))))/3=26

We move all terms to the left:

((n-1)(4(n-1))(2(4(n-1))))/3-(26)=0

We multiply all the terms by the denominator


((n-1)(4(n-1))(2(4(n-1))))-26*3=0



We calculate terms in parentheses: +((n-1)(4(n-1))(2(4(n-1)))), so:

(n-1)(4(n-1))(2(4(n-1)))



We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





We calculate terms in parentheses: +(n-1)(4(n-1))(2(4(n-1))), so:

n-1)(4(n-1))(2(4(n-1))





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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