((k+4)/4)+((k-1)/4)=(k+4)/4k

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Solution for ((k+4)/4)+((k-1)/4)=(k+4)/4k equation: 


k in (-oo:+oo)

(k+4)/4+(k-1)/4 = k*((k+4)/4) // - k*((k+4)/4)

(k+4)/4+(k-1)/4-(k*((k+4)/4)) = 0

(k+4)/4+(k-1)/4+(-1*k*(k+4))/4 = 0

k-1*k*(k+4)+k-1+4 = 0

2*k-k^2-4*k+3 = 0

3-k^2-2*k = 0

3-k^2-2*k = 0

3-k^2-2*k = 0

DELTA = (-2)^2-(-1*3*4)

DELTA = 16

DELTA > 0

k = (16^(1/2)+2)/(-1*2) or k = (2-16^(1/2))/(-1*2)

k = -3 or k = 1

(k+3)*(k-1) = 0

((k+3)*(k-1))/4 = 0

((k+3)*(k-1))/4 = 0 // * 4

(k+3)*(k-1) = 0

( k+3 )

k+3 = 0 // - 3

k = -3

( k-1 )

k-1 = 0 // + 1

k = 1

k in { -3, 1 }

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