((a+1)/5a)-(1/a)=1

Solution for ((a+1)/5a)-(1/a)=1 equation:

((a+1)/5a)-(1/a)=1

We move all terms to the left:

((a+1)/5a)-(1/a)-(1)=0


Domain of the equation: 5a)!=0

a!=0/1

a!=0

a∈R



Domain of the equation: a)!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

((a+1)/5a)-(+1/a)-1=0

We get rid of parentheses

((a+1)/5a)-1/a-1=0

We calculate fractions


(((a+1)*a)/5a*a)+(-5a)/5a*a)-1=0


We calculate terms in parentheses: +(((a+1)*a)/5a*a), so:

((a+1)*a)/5a*a

We multiply all the terms by the denominator


((a+1)*a)


We calculate terms in parentheses: +((a+1)*a), so:

(a+1)*a

We multiply parentheses

a^2+a

Back to the equation:

+(a^2+a)


We get rid of parentheses

a^2+a

Back to the equation:

+(a^2+a)


We get rid of parentheses

a^2+a+(-5a)/5a*a)-1=0

We multiply all the terms by the denominator


a^2*5a*a)-1+a*5a*a)-1+(-5a)=0

Wy multiply elements

25a^6*a=0

We do not support eapression: a^6