((X-5)/8)+((x+2)/3)=9/8

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Solution for ((X-5)/8)+((x+2)/3)=9/8 equation: 



((X-5)/8)+((X+2)/3)=9/8

We move all terms to the left:

((X-5)/8)+((X+2)/3)-(9/8)=0

We add all the numbers together, and all the variables

((X-5)/8)+((X+2)/3)-(+9/8)=0

We get rid of parentheses

((X-5)/8)+((X+2)/3)-9/8=0

We calculate fractions


(3X-15)/()+(((X+2)*8)*8)/()+()/()=0



We calculate terms in parentheses: +(((X+2)*8)*8)/(), so:

((X+2)*8)*8)/(

We multiply all the terms by the denominator


((X+2)*8)*8)



We calculate terms in parentheses: +((X+2)*8)*8), so:

(X+2)*8)*8

We multiply parentheses

8X+

We add all the numbers together, and all the variables

8X

Back to the equation:

+(8X)



Back to the equation:

+(8X)



We add all the numbers together, and all the variables

8X+(3X-15)/()+1=0

We multiply all the terms by the denominator


8X*()+(3X-15)+1*()=0

We add all the numbers together, and all the variables

8X*()+(3X-15)=0

We get rid of parentheses

8X*()+3X-15=0

We add all the numbers together, and all the variables

3X+8X*()-15=0

We move all terms containing X to the left, all other terms to the right

3X+8X*()=15

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