((7x-6)/3)((x-4)/5)=-2

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Solution for ((7x-6)/3)((x-4)/5)=-2 equation: 


x in (-oo:+oo)

((7*x-6)/3)*((x-4)/5) = -2 // + 2

((7*x-6)/3)*((x-4)/5)+2 = 0

((7*x-6)*(x-4))/(3*5)+2 = 0

((7*x-6)*(x-4))/(3*5)+(2*3*5)/(3*5) = 0

(7*x-6)*(x-4)+2*3*5 = 0

7*x^2-34*x+54 = 0

7*x^2-34*x+54 = 0

7*x^2-34*x+54 = 0

DELTA = (-34)^2-(4*7*54)

DELTA = -356

DELTA < 0

1 = 0

1/(3*5) = 0

1/(3*5) = 0 // * 3*5

1 = 0

x belongs to the empty set

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