((7)/(y-5))/((28)/(3y-15))

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Solution for ((7)/(y-5))/((28)/(3y-15)) equation: 


D( y )

3*y-15 = 0

28/(3*y-15) = 0

y-5 = 0

3*y-15 = 0

3*y-15 = 0

3*y-15 = 0 // + 15

3*y = 15 // : 3

y = 15/3

y = 5

28/(3*y-15) = 0

28/(3*y-15) = 0

28 = 0

y belongs to the empty set

y-5 = 0

y-5 = 0

y-5 = 0 // + 5

y = 5

y in (-oo:5) U (5:+oo)

(7/(y-5))/(28/(3*y-15)) = 0

(7*(3*y-15))/(28*(y-5)) = 0

( 3*y-15 )

3*y-15 = 0 // + 15

3*y = 15 // : 3

y = 15/3

y = 5

( 7 )

7 = 0

y belongs to the empty set

y in { 5} 

y belongs to the empty set

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