((63x)+65(100-x))/100=63.55

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Solution for ((63x)+65(100-x))/100=63.55 equation: 



((63x)+65(100-x))/100=63.55

We move all terms to the left:

((63x)+65(100-x))/100-(63.55)=0

We add all the numbers together, and all the variables

(63x+65(-1x+100))/100-(63.55)=0

We add all the numbers together, and all the variables

(63x+65(-1x+100))/100-63.55=0

We multiply all the terms by the denominator


(63x+65(-1x+100))-(63.55)*100=0



We calculate terms in parentheses: +(63x+65(-1x+100)), so:

63x+65(-1x+100)

We multiply parentheses

63x-65x+6500

We add all the numbers together, and all the variables

-2x+6500

Back to the equation:

+(-2x+6500)



We add all the numbers together, and all the variables

(-2x+6500)-6355=0

We get rid of parentheses

-2x+6500-6355=0

We add all the numbers together, and all the variables

-2x+145=0

We move all terms containing x to the left, all other terms to the right

-2x=-145

x=-145/-2

x=72+1/2

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