((6/11)n)+35=-7

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Solution for ((6/11)n)+35=-7 equation:



((6/11)n)+35=-7
We move all terms to the left:
((6/11)n)+35-(-7)=0
Domain of the equation: 11)n)!=0
n!=0/1
n!=0
n∈R
We add all the numbers together, and all the variables
((+6/11)n)+35-(-7)=0
We add all the numbers together, and all the variables
((+6/11)n)+42=0
We multiply all the terms by the denominator
((+6+42*11)n)=0
We calculate terms in parentheses: +((+6+42*11)n), so:
(+6+42*11)n
We add all the numbers together, and all the variables
468n
Back to the equation:
+(468n)
n=0/468
n=0
Równanie nie ma rozwiązania

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