((50x+20)/2)+(36-18)=2x+4

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Solution for ((50x+20)/2)+(36-18)=2x+4 equation: 



((50x+20)/2)+(36-18)=2x+4

We move all terms to the left:

((50x+20)/2)+(36-18)-(2x+4)=0

We add all the numbers together, and all the variables

((50x+20)/2)-(2x+4)+18=0

We get rid of parentheses

((50x+20)/2)-2x-4+18=0

We multiply all the terms by the denominator


((50x+20)-2x*2)-4*2)+18*2)=0



We calculate terms in parentheses: +((50x+20)-2x*2), so:

(50x+20)-2x*2

Wy multiply elements

(50x+20)-4x

We get rid of parentheses

50x-4x+20

We add all the numbers together, and all the variables

46x+20

Back to the equation:

+(46x+20)



We add all the numbers together, and all the variables

(46x+20)=0

We get rid of parentheses

46x+20=0

We move all terms containing x to the left, all other terms to the right

46x=-20

x=-20/46

x=-10/23

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