((5+h)/12)+((h-3)/4)=1/3

Solution for ((5+h)/12)+((h-3)/4)=1/3 equation:

((5+h)/12)+((h-3)/4)=1/3

We move all terms to the left:

((5+h)/12)+((h-3)/4)-(1/3)=0

We add all the numbers together, and all the variables

((h+5)/12)+((h-3)/4)-(+1/3)=0

We get rid of parentheses

((h+5)/12)+((h-3)/4)-1/3=0

We calculate fractions


(((h+5)*4)*3)/()+(((h-3)*12)*3)/()+()/()=0


We calculate terms in parentheses: +(((h+5)*4)*3)/(), so:

((h+5)*4)*3)/(

We multiply all the terms by the denominator


((h+5)*4)*3)


We calculate terms in parentheses: +((h+5)*4)*3), so:

(h+5)*4)*3

We multiply parentheses

3h+

We add all the numbers together, and all the variables

3h

Back to the equation:

+(3h)


Back to the equation:

+(3h)



We calculate terms in parentheses: +(((h-3)*12)*3)/(), so:

((h-3)*12)*3)/(

We multiply all the terms by the denominator


((h-3)*12)*3)


We calculate terms in parentheses: +((h-3)*12)*3), so:

(h-3)*12)*3

We multiply parentheses

3h+

We add all the numbers together, and all the variables

3h

Back to the equation:

+(3h)


Back to the equation:

+(3h)


We add all the numbers together, and all the variables

6h+1=0

We move all terms containing h to the left, all other terms to the right

6h=-1

h=-1/6

h=-1/6