((4y+6)+(7y-7))+(20y-11)=360

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Solution for ((4y+6)+(7y-7))+(20y-11)=360 equation: 



((4y+6)+(7y-7))+(20y-11)=360

We move all terms to the left:

((4y+6)+(7y-7))+(20y-11)-(360)=0

We get rid of parentheses

((4y+6)+(7y-7))+20y-11-360=0



We calculate terms in parentheses: +((4y+6)+(7y-7)), so:

(4y+6)+(7y-7)

We get rid of parentheses

4y+7y+6-7

We add all the numbers together, and all the variables

11y-1

Back to the equation:

+(11y-1)



We add all the numbers together, and all the variables

20y+(11y-1)-371=0

We get rid of parentheses

20y+11y-1-371=0

We add all the numbers together, and all the variables

31y-372=0

We move all terms containing y to the left, all other terms to the right

31y=372

y=372/31

y=12

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