((4x-8)/2)=(10x/5)-2

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Solution for ((4x-8)/2)=(10x/5)-2 equation: 


x in (-oo:+oo)

(4*x-8)/2 = (10*x)/5-2 // - (10*x)/5-2

(4*x-8)/2-((10*x)/5)+2 = 0

(4*x-8)/2-2*x+2 = 0

(4*x-8)/2+(-2*2*x)/2+(2^2)/2 = 0

4*x-2*2*x-8+4 = 0

4-8 = 0

-4 = 0

-4/2 = 0

-4/2 = 0 // * 2

-4 = 0

-4 = 0

x belongs to the empty set

x belongs to the empty set

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