((4x)/(x-4))-(4/(x-2))=-2

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Solution for ((4x)/(x-4))-(4/(x-2))=-2 equation: 


D( x )

x-2 = 0

x-4 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:2) U (2:4) U (4:+oo)

(4*x)/(x-4)-(4/(x-2)) = -2 // + 2

(4*x)/(x-4)-(4/(x-2))+2 = 0

(4*x)/(x-4)-4*(x-2)^-1+2 = 0

(4*x)/(x-4)-4/(x-2)+2 = 0

(4*x*(x-2))/((x-4)*(x-2))+(-4*(x-4))/((x-4)*(x-2))+(2*(x-4)*(x-2))/((x-4)*(x-2)) = 0

4*x*(x-2)-4*(x-4)+2*(x-4)*(x-2) = 0

4*x^2+2*x^2-12*x-12*x+16+16 = 0

6*x^2-24*x+32 = 0

6*x^2-24*x+32 = 0

2*(3*x^2-12*x+16) = 0

3*x^2-12*x+16 = 0

DELTA = (-12)^2-(3*4*16)

DELTA = -48

DELTA < 0

2 = 0

2/((x-4)*(x-2)) = 0

2/((x-4)*(x-2)) = 0 // * (x-4)*(x-2)

2 = 0

x belongs to the empty set

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