((4b-8)/3)=2b

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Solution for ((4b-8)/3)=2b equation: 



((4b-8)/3)=2b

We move all terms to the left:

((4b-8)/3)-(2b)=0

We add all the numbers together, and all the variables

-2b+((4b-8)/3)=0

We multiply all the terms by the denominator


-2b*3)+((4b-8)=0

Wy multiply elements

-6b^2=0

a = -6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-6)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-12}=0$

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