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D( x )
(5*x-15)/7 = 0
(5*x-15)/7 = 0
(5*x-15)/7 = 0
5*x-15 = 0 // + 15
5*x = 15 // : 5
x = 15/5
x = 3
x in (-oo:3) U (3:+oo)
((3*x-9)/5)/((5*x-15)/7) = 0
(7*(3*x-9))/(5*(5*x-15)) = 0
3*x-9 = 0 // + 9
3*x = 9 // : 3
x = 9/3
x = 3
x in { 3}
x belongs to the empty set
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