((3x-18)*(x+10))-(3x*x)=12

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Solution for ((3x-18)*(x+10))-(3x*x)=12 equation: 



((3x-18)(x+10))-(3x*x)=12

We move all terms to the left:

((3x-18)(x+10))-(3x*x)-(12)=0

We add all the numbers together, and all the variables

((3x-18)(x+10))-(+3x*x)-12=0

We get rid of parentheses

((3x-18)(x+10))-3x*x-12=0

We multiply parentheses ..

((+3x^2+30x-18x-180))-3x*x-12=0



We calculate terms in parentheses: +((+3x^2+30x-18x-180)), so:

(+3x^2+30x-18x-180)

We get rid of parentheses

3x^2+30x-18x-180

We add all the numbers together, and all the variables

3x^2+12x-180

Back to the equation:

+(3x^2+12x-180)



Wy multiply elements

-3x^2+(3x^2+12x-180)-12=0

We get rid of parentheses

-3x^2+3x^2+12x-180-12=0

We add all the numbers together, and all the variables

12x-192=0

We move all terms containing x to the left, all other terms to the right

12x=192

x=192/12

x=16

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