((3x-1)/4)-3/x-1=0

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Solution for ((3x-1)/4)-3/x-1=0 equation: 



((3x-1)/4)-3/x-1=0



Domain of the equation: x!=0

x∈R



We calculate fractions


(((3x-1)*x)/4*x)+()/4*x)-1=0



We calculate terms in parentheses: +(((3x-1)*x)/4*x), so:

((3x-1)*x)/4*x

We multiply all the terms by the denominator


((3x-1)*x)



We calculate terms in parentheses: +((3x-1)*x), so:

(3x-1)*x

We multiply parentheses

3x^2-1x

Back to the equation:

+(3x^2-1x)



We get rid of parentheses

3x^2-1x

Back to the equation:

+(3x^2-1x)



We get rid of parentheses

3x^2-1x+()/4*x)-1=0

We multiply all the terms by the denominator


3x^2*4*x)-1-1x*4*x)-1+()=0

Wy multiply elements

48x^4*x=0

We do not support expression: x^4

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