((3x-1)/2)-((x+1)/3)=2

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Solution for ((3x-1)/2)-((x+1)/3)=2 equation: 



((3x-1)/2)-((x+1)/3)=2

We move all terms to the left:

((3x-1)/2)-((x+1)/3)-(2)=0

We calculate fractions


(9x-3)/()+(-2x-2)/()-2=0

We multiply all the terms by the denominator


(9x-3)+(-2x-2)-2*()=0

We add all the numbers together, and all the variables

(9x-3)+(-2x-2)=0

We get rid of parentheses

9x-2x-3-2=0

We add all the numbers together, and all the variables

7x-5=0

We move all terms containing x to the left, all other terms to the right

7x=5

x=5/7

x=5/7

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