((3k)/(k-2))+((6)/(2-k))

Solution for ((3k)/(k-2))+((6)/(2-k)) equation:

D( k )

2-k = 0

k-2 = 0

2-k = 0

2-k = 0

2-k = 0 // - 2

-k = -2 // * -1

k = 2

k-2 = 0

k-2 = 0

k-2 = 0 // + 2

k = 2

k in (-oo:2) U (2:+oo)

(3*k)/(k-2)+6/(2-k) = 0

(3*k*(2-k))/((k-2)*(2-k))+(6*(k-2))/((k-2)*(2-k)) = 0

3*k*(2-k)+6*(k-2) = 0

12*k-3*k^2-12 = 0

12*k-3*k^2-12 = 0

3*(4*k-k^2-4) = 0

4*k-k^2-4 = 0

DELTA = 4^2-(-4*(-1)*4)

DELTA = 0

k = -4/(-1*2)

k = 2 or k = 2

3*(k-2)^2 = 0

(3*(k-2)^2)/((k-2)*(2-k)) = 0

(3*(k-2)^2)/((k-2)*(2-k)) = 0 // * (k-2)*(2-k)

3*(k-2)^2 = 0

k-2 = 0 // + 2

k = 2

k in { 2} 

k belongs to the empty set