((2x-8)/3)+5=0

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Solution for ((2x-8)/3)+5=0 equation:



((2x-8)/3)+5=0
We multiply all the terms by the denominator
((2x-8)+5*3)=0
We calculate terms in parentheses: +((2x-8)+5*3), so:
(2x-8)+5*3
We add all the numbers together, and all the variables
(2x-8)+15
We get rid of parentheses
2x-8+15
We add all the numbers together, and all the variables
2x+7
Back to the equation:
+(2x+7)
We get rid of parentheses
2x+7=0
We move all terms containing x to the left, all other terms to the right
2x=-7
x=-7/2
x=-3+1/2

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