((2x-3)/7)+(3/7)=-(x/3)

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Solution for ((2x-3)/7)+(3/7)=-(x/3) equation: 



((2x-3)/7)+(3/7)=-(x/3)

We move all terms to the left:

((2x-3)/7)+(3/7)-(-(x/3))=0

We add all the numbers together, and all the variables

((2x-3)/7)-(-(+x/3))+(+3/7)=0

We get rid of parentheses

((2x-3)/7)-(-(+x/3))+3/7=0

We calculate fractions


2x/()+(-(-(+x*7)*7)/()+()/()=0



We calculate terms in parentheses: +(-(-(+x*7)*7)/()+()/(), so:

-(-(+x*7)*7)/()+()/(

We add all the numbers together, and all the variables

-(-(+x*7)*7)/()+1

We multiply all the terms by the denominator


-(-(+x*7)*7)+1*()



We calculate terms in parentheses: -(-(+x*7)*7), so:

-(+x*7)*7

We multiply parentheses

-49x

Back to the equation:

-(-49x)



We add all the numbers together, and all the variables

-(-49x)

We get rid of parentheses

49x

Back to the equation:

+(49x)



We add all the numbers together, and all the variables

49x+2x/()=0

We multiply all the terms by the denominator


49x*()+2x=0

We add all the numbers together, and all the variables

2x+49x*()=0

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